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The magnitude of each force is 208 N. The force on the right is applied at an angle of 36°, and the mass of the block is 17 kg. The coefficient of friction is 0.149. The acceleration of gravity is 9.8 m/s\(^2\).

What is the magnitude of the resulting acceleration?

Answer in units of m/s\(^2\).

Answer :

Answer:

11.06m/s²

Explanation:

According to Newtons second law of motion

[tex]\sm F_x = ma_x\\F_m - F_f = ma_x\\mgsin \theta - \mu R mgcos \theta = ma_x\\[/tex]

Given

Mass m = 17kg

Fm = 208N

theta = 36 degrees

g = 9.8m/s²

a is the acceleration

Substitute

208 - 0.148(17)(9.8)cos 36 = 17a

208 - 24.6568cos36 = 17a

208 - 19.9478 = 17a

188.05 = 17a

a = 188.05/17

a = 11.06m/s²

Hence the the magnitude of the resulting acceleration is 11.06m/s²

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