Answer :
Answer: 525 cycles per second.
Step-by-step explanation:
The equation for inverse variation between x and y is given by :-
[tex]x_1y_1=x_2y_2[/tex] (1)
Given : The length of a violin string varies inversely with the frequency of its vibrations.
A violin string 14 inches long vibrates at a frequency of 450 cycles per second.
Let x = length of a violin
y= frequency of its vibrations
To find: The frequency of a 12 inch violin string.
Put [tex]x_1=14,\ x_2=12\\y_1=450,\ y_2=y[/tex] in equation (1) , we get
[tex](14)(450)=(12)(y)[/tex]
Divide both sides by 12 , we get
[tex]y=\dfrac{(14)(450)}{12}=525[/tex]
Hence, the frequency of a 12 inch violin string = 525 cycles per second.
Final answer:
The frequency of a 12 inch violin string is approximately 388.57 cycles per second.
Explanation:
The length of a violin string varies inversely with the frequency of its vibrations. This means that as the length of the string decreases, the frequency of the vibrations increases, and vice versa. To find the frequency of a 12 inch violin string, we can set up the following proportion:
14 inches / 450 cycles per second = 12 inches / x cycles per second
To solve for x, we can cross multiply:
14 inches * x cycles per second = 12 inches * 450 cycles per second
x = (12 inches * 450 cycles per second) / 14 inches
Simplifying:
x = 388.57 cycles per second
Therefore, the frequency of a 12 inch violin string is approximately 388.57 cycles per second.
Learn more about Frequency of vibrations here:
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