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------------------------------------------------ The length of a rectangular parking area is two times the width. The perimeter is 120 yards. Find the length and width of the parking area.

To solve this problem, we need to find the length and width of a rectangular parking area given some conditions:

1. Understand the Problem:
- The length of the rectangular parking area is two times the width.
- The perimeter of the rectangle is 120 yards.

2. Set Up the Equations:
- Let's denote the width of the rectangle as [tex]\( x \)[/tex].
- Since the length is two times the width, the length will be [tex]\( 2x \)[/tex].

3. Formula for Perimeter:
- The formula for the perimeter of a rectangle is calculated as:
[tex]\[
\text{Perimeter} = 2(\text{Length} + \text{Width})
\][/tex]
- Substituting the expressions for the length and width, we have:
[tex]\[
120 = 2(2x + x)
\][/tex]

4. Simplify and Solve the Equation:
- Simplify inside the parentheses:
[tex]\[
120 = 2(3x) = 6x
\][/tex]
- Solve for [tex]\( x \)[/tex] by dividing both sides by 6:
[tex]\[
x = \frac{120}{6} = 20
\][/tex]

5. Find Length and Width:
- Now that we have [tex]\( x = 20 \)[/tex], which represents the width,
- Calculate the length as [tex]\( 2x \)[/tex]:
[tex]\[
\text{Length} = 2 \times 20 = 40
\][/tex]

Therefore, the width of the parking area is 20 yards, and the length is 40 yards.