Answer :
Final answer:
The test statistic result is 1.63, which is less than the critical value of ±2.712. Therefore, we can't reject the null hypothesis and so we cannot conclude that the mean weight of bears in Yellowstone National Park is significantly different from 187lb.
Explanation:
In this scenario, we are performing a hypothesis test for the mean weight of bears in Yellowstone National Park using periodic measurements. We will use a two-tailed t-test in this case because we want to know if the average weight is significantly different from 187lb, either higher or lower.
- (a) Test Statistic: The formula for the test statistic in a one sample t-test is: (sample mean - population mean) / (standard deviation/sqrt(number of observations)). Substituting the given values, we get: (189.2 - 187) / (8.3/sqrt(39)) = 1.63.
- (b) Critical Value: At α=.01 for a two-tailed test, the degrees of freedom is n - 1, which equals 38. Checking the t-distribution table, the critical value for df=38 at α=.01 is ±2.712.
- (c) P-Value: Since our calculated test statistic (1.63) falls within the critical region (-2.712,+2.712), we cannot reject the null hypothesis. However, the exact p-value needs to be looked up in the t-distribution table or calculated with statistical software.
- (d) Conclusion: Since we cannot reject the null hypothesis, statistically we conclude that there is no significant evidence to say that the mean weight of bears in Yellowstone National Park is significantly different from 187lb at the 1% level of significance.
Learn more about Hypothesis Testing here:
https://brainly.com/question/31665727
#SPJ11