Answer :
Final answer:
The gauge pressure in the same liquid at a depth of 10 m is approximately 88.24 kPa.
Explanation:
To determine the gauge pressure in the same liquid at a depth of 10 m, we can use the formula for gauge pressure in a liquid: P = ρgh.
Given:
- Depth at which gauge pressure is known: 5.1 m
- Gauge pressure at that depth: 45 kPa
We need to find the gauge pressure at a depth of 10 m.
Since the density of the liquid and the acceleration due to gravity are constant, we can set up a proportion:
P1 / h1 = P2 / h2
Substituting the given values:
45 kPa / 5.1 m = P2 / 10 m
Cross-multiplying and solving for P2:
P2 = (45 kPa / 5.1 m) * 10 m
Simplifying:
P2 = 88.24 kPa
Therefore, the gauge pressure in the same liquid at a depth of 10 m is approximately 88.24 kPa.
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Final answer:
To determine the gauge pressure in the same liquid at a depth of 10 m, we can use the equation for hydrostatic pressure: p = hρg. Since the density of the liquid is not provided, we assume it is constant and use the same density value as in the previous question.
Explanation:
To determine the gauge pressure in the same liquid at a depth of 10 m, we can use the equation for hydrostatic pressure:
p = hρg
Where p is the pressure, h is the depth, ρ is the density of the liquid, and g is the acceleration due to gravity. Since the density of the liquid is not provided, we can't calculate the exact pressure. However, we can assume that the density of the liquid is constant and use the same density value as in the previous question. Using this assumption, we can calculate the pressure as follows:
p = (10 m - 5.1 m) × ρ × 9.81 m/s²
Substituting the values, we can calculate the pressure at a depth of 10 m.
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