High School

The function [tex]f(t) = 7000 \cdot e^{-6t}[/tex] represents the rate of flow of money in dollars per year. Assume a 10-year period.

What is the rate of flow of money at [tex]t = 8[/tex]?

1) [tex]7000 \cdot e^{-48}[/tex]
2) [tex]7000 \cdot e^{-56}[/tex]
3) [tex]7000 \cdot e^{-64}[/tex]
4) [tex]7000 \cdot e^{-72}[/tex]

Answer :

Final answer:

The rate of flow of money at t = 8 is found by substituting 8 into the function, giving f(8) = 7000 * e^(-48). Therefore, the correct answer is 1) 7000 * e^(-48).

Explanation:

The function f(t) = 7000 * e^(-6 * t) models the flow of money, in dollars per year, over a specified time period ‘t’. When we want to find the rate of money flow at t = 8, we substitute 8 into the function giving us f(8) = 7000 * e^(-6 * 8). This simplifies to f(8) = 7000 * e^(-48). Thus, the correct answer is option 1) 7000 * e^(-48).

Learn more about Exponential Decay here:

https://brainly.com/question/12900684

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