High School

The force of gravity pulling on an object down a hill is its weight multiplied by the sine of the angle of elevation of the hill.

With how many pounds of force is gravity pulling on a 3000 lb car on a hill with a 3-degree angle of elevation?

Calculation:
\(\sin(3^\circ) \approx 0.0523\)
\(0.0523 \times 3000 \approx 157 \text{ lbs (rounded)}\)

Is this correct?

Answer :

Final answer:

The force of gravity pulling on a 3000 lb car on a hill with a 3 degree angle of elevation is approximately 157 lbs.

Explanation:

To find the force of gravity pulling on a car on a hill with a 3 degree angle of elevation, you need to multiply the weight of the car by the sine of the angle. First, find the sine of 3 degrees, which is approximately 0.0523. Then, multiply 0.0523 by the weight of the car (3000 lbs). The calculation is correct, and the force of gravity pulling on the 3000 lb car on a hill with a 3 degree angle of elevation is approximately 157 lbs.

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