High School

The engine torque [tex]$y$[/tex] (in foot-pounds) of one model of car is given by the equation [tex]$y = -3.75x^2 + 23.2x + 38.8$[/tex], where [tex]$x$[/tex] is the speed (in thousands of revolutions per minute) of the engine.

a. To the nearest ten, what is the engine speed that maximizes torque?

Answer :

Final answer:

The engine speed that maximizes torque is approximately 3100 revolutions per minute.

Explanation:

To find the engine speed that maximizes torque, we need to find the vertex of the quadratic function.

The vertex can be found using the formula x = -b/2a, where a is the coefficient of the quadratic term and b is the coefficient of the linear term.

In this case, the quadratic function is y = -3.75x^2 + 23.2x + 38.8.

Plugging in the values, we get x = -23.2/(2*-3.75) = 3.1.

Therefore, the engine speed that maximizes torque is approximately 3100 revolutions per minute.

Learn more about Maximizing torque here:

https://brainly.com/question/30219374

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