Answer :
Final answer:
The distance the car travels while the driver applies the breaks is 66.15 meters.
Explanation:
This question is about calculating the distance a car travels when the driver applies the breaks to slow down before it stops. We can use the formula for distance (d) under constant acceleration: d = v*t + 0.5*a*t2. However, because the car comes to a stop, we know that its final velocity (vf) is 0 m/s. Therefore, we can use a modified version of the equation: d = 0.5*(vi+vf)*t where vi is the initial velocity.
Let's plug in the values:
d = 0.5*(21 m/s + 0 m/s)*6.3 s = 66.15 meters.
So, the car travels a distance of 66.15 meters while the brakes are applied.
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