Answer :
Final answer:
The corresponding value of the density of gold in the CGS system is [tex]20 g/cm^{3}[/tex].
Explanation:
To convert the density of gold from the SI system ([tex]kg/m^{3}[/tex]) to the CGS system ([tex]g/cm^{3}[/tex]), we need to convert the units of mass and volume.
Given: [tex]Density\; of\; gold = 20000\; kg/m^{3}[/tex]
Conversion factors:
- [tex]1 kg = 1000 g[/tex]
- [tex]1 m^{3} = 1000000\; cm^{3}[/tex]
First, let's convert the mass:
[tex]Mass\; in\; grams = 20000\; kg \times 1000 g/kg = 20000000\; g[/tex]
Next, let's convert the volume:
[tex]Volume\; in\; cm^{3} = 1\; m^{3} \times 1000000\; cm^{3}/m^{3} = 1000000\; cm^{3}[/tex]
We can now determine the CGS system's density:
[tex]Density\; in\; g/cm^{3} = \frac{Mass\; in\; grams}{Volume\; in\; cm^{3}}[/tex]
[tex]Density\; in\; g/cm^{3} = \frac{20000000 g}{1000000 cm^{3}} = 20 g/cm^{3}[/tex]
Learn more about si to cgs system here:
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