High School

The compound that dried in Beaker #1 has a tendency to form a hydrate at room temperature.

1. How would the error of this experiment have been affected if you had massed Beaker #1 as soon as you arrived for week two? Why?

2. Why were the filter paper and the solid it contained allowed to air dry all week and not heated in the drying oven?

3. How would the percentage error of the experiment have been affected if the sample had been heated in the drying oven for a week? Be specific; comment on whether the calculated value will appear to be too high or too low.

Answer :

Massing beaker #1 immediately upon arrival would result in an overestimation of the compound's mass due to the presence of water molecules, while air drying the filter paper and solid preserves the compound's integrity, and heating the sample in the drying oven would cause a lower measured mass and a calculated percentage lower than the actual value.

If beaker #1, containing a compound that tends to form a hydrate at room temperature, was massed as soon as I arrived for week two, the error of the experiment would likely be affected. This is because the compound would not have had enough time to fully dehydrate and reach a constant mass. Therefore, the measured mass would include the mass of both the compound and the water molecules present in the hydrate, leading to an overestimation of the compound's mass. This would introduce a systematic error in the experiment, causing the calculated percentage of the compound in the original mixture to appear higher than its actual value.

The filter paper and solid contained within it were allowed to air dry all week instead of being heated in the drying oven because heating in the oven could lead to the loss of volatile components and disrupt the stability of the compound. The aim is to remove only the water molecules from the hydrate while preserving the integrity of the compound.

If the sample had been heated in the drying oven for a week, the percentage error of the experiment would likely be affected. Heating the sample would cause the water molecules to evaporate more rapidly, resulting in a lower measured mass of the compound. Consequently, the calculated percentage of the compound in the original mixture would appear lower than its actual value.

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