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------------------------------------------------ The bulkhead is subjected to both water and soil-backfill pressures. The bulkhead has a mass of 800 kg. Suppose that [tex]w_{\text{water}} = 118 \, \text{kN/m}[/tex] and [tex]w_{\text{soil}} = 330 \, \text{kN/m}[/tex]. What is the total pressure acting on the bulkhead?

The bulkhead ad is subjected to both water and soil-backfill pressures, the bulkhead has a mass of 800 kg, the total pressure acting on the bulkhead is 358.4 kN.

Explanation:

To calculate the total pressure acting on the bulkhead, we need to consider the pressures exerted by both water and soil-backfill.

Given:

- Mass of the bulkhead = 800 kg

- Pressure due to water (wwater) = 118 kN/m

- Pressure due to soil-backfill (wsoil) = 330 kN/m

To find the total pressure, we need to calculate the total force acting on the bulkhead.

This force is the sum of the forces due to water and soil-backfill pressures acting on the bulkhead.

1. Calculate the force due to water pressure:

Force due to water pressure = wwater * area

Area = mass / density = 800 kg / 1000 kg/m³ = 0.8 m²

Force due to water pressure = 118 kN/m * 0.8 m² = 94.4 kN

2. Calculate the force due to soil-backfill pressure:

Force due to soil-backfill pressure = wsoil * area

Force due to soil-backfill pressure = 330 kN/m * 0.8 m² = 264 kN

3. Calculate the total pressure acting on the bulkhead:

Total pressure = Force due to water pressure + Force due to soil-backfill pressure

Total pressure = 94.4 kN + 264 kN = 358.4 kN

Therefore, the total pressure acting on the bulkhead is 358.4 kN.