The braking distance of a car varies directly as the square of the speed of the car. Assume that a car traveling at 30 miles per hour (mph) can stop in 43 feet after the brakes are applied. How long is the braking distance for that same car traveling at 60 mph?

By using the ratio of the squares of the speeds, we find that the braking distance at 60 mph is four times the braking distance at 30 mph. Therefore, the braking distance for the car traveling at 60 mph is 4 times 43 feet, which is 172 feet.

Let's denote the braking distance at 30 mph as D1 and the braking distance at 60 mph as D2. According to the given information, we have the following relationship: D1 ∝ (30)^2 and D2 ∝ (60)^2.

To find the ratio between D2 and D1, we can take the square of the ratio of the speeds: (60/30)^2 = 2^2 = 4.

This indicates that the braking distance at 60 mph is four times the braking distance at 30 mph.

Given that the braking distance at 30 mph is 43 feet, we can multiply this distance by 4 to find the braking distance at 60 mph: 43 feet * 4 = 172 feet.

Therefore, the braking distance for the same car traveling at 60 mph is 172 feet.

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