Answer :
We start by noting that the tip of the windmill blade moves in a circular path. The sine model for the height is given by
[tex]$$
y = a \sin(b t) + k.
$$[/tex]
1. Since the blades are 15 feet long, the amplitude (which is the distance from the center of the circle to the tip) is
[tex]$$
a = 15.
$$[/tex]
2. The axis of the windmill is 40 feet from the ground. This means that the center of the circular motion is 40 feet above the ground. Thus, the vertical shift is
[tex]$$
k = 40.
$$[/tex]
3. (For context, although not required for the values asked) The windmill makes 3 rotations per minute, meaning the period is
[tex]$$
T = \frac{60 \text{ seconds}}{3} = 20 \text{ seconds}.
$$[/tex]
Thus, the angular frequency is computed as
[tex]$$
b = \frac{2\pi}{T} = \frac{2\pi}{20} = \frac{\pi}{10}.
$$[/tex]
So, the sine model for the height of the end of one blade is
[tex]$$
y = 15 \sin\left(\frac{\pi}{10}t\right) + 40.
$$[/tex]
In summary:
- The amplitude, [tex]$a$[/tex], is the radius of the circular motion and is 15.
- The vertical shift, [tex]$k$[/tex], is the height of the windmill’s axis, which is 40.
Thus, the answers are:
[tex]$$
a = 15 \quad \text{and} \quad k = 40.
$$[/tex]
[tex]$$
y = a \sin(b t) + k.
$$[/tex]
1. Since the blades are 15 feet long, the amplitude (which is the distance from the center of the circle to the tip) is
[tex]$$
a = 15.
$$[/tex]
2. The axis of the windmill is 40 feet from the ground. This means that the center of the circular motion is 40 feet above the ground. Thus, the vertical shift is
[tex]$$
k = 40.
$$[/tex]
3. (For context, although not required for the values asked) The windmill makes 3 rotations per minute, meaning the period is
[tex]$$
T = \frac{60 \text{ seconds}}{3} = 20 \text{ seconds}.
$$[/tex]
Thus, the angular frequency is computed as
[tex]$$
b = \frac{2\pi}{T} = \frac{2\pi}{20} = \frac{\pi}{10}.
$$[/tex]
So, the sine model for the height of the end of one blade is
[tex]$$
y = 15 \sin\left(\frac{\pi}{10}t\right) + 40.
$$[/tex]
In summary:
- The amplitude, [tex]$a$[/tex], is the radius of the circular motion and is 15.
- The vertical shift, [tex]$k$[/tex], is the height of the windmill’s axis, which is 40.
Thus, the answers are:
[tex]$$
a = 15 \quad \text{and} \quad k = 40.
$$[/tex]