High School

The average body temperature of a healthy adult is 98.6 degrees Fahrenheit. Jenny is concerned that her temperature is elevated, so she took her temperature on 5 randomly chosen occasions. Her average temperature was 99.3 degrees Fahrenheit.

Let [tex]x[/tex] be a random variable that represents Jenny's body temperature. Assume that [tex]x[/tex] has a normal distribution with a standard deviation [tex]\sigma = 0.73[/tex].

Test at the 1% significance level. Find the critical value of [tex]x[/tex].

1) 2.33
2) 1.96
3) 1.64
4) 2.58

Answer :

Final answer:

The question is about performing a t-test to check if Jenny's body temperature is significantly higher than the average, but the sample size information is missing to proceed. The provided critical values seem to be z-scores, which are not applicable for a t-test with an unknown population standard deviation.

Explanation:

The student seems to be asking how to test whether Jenny's body temperature is significantly higher than the standard average body temperature of 98.6°F, given that she has a sample average of 99.3°F and a known sample standard deviation (s) of 0.73°F. Since the standard deviation of the population is not known, a t-test would be more appropriate than a z-test. However, the student's question is incomplete as it does not provide the sample size for Jenny's temperature readings, which is critical for determining the degrees of freedom required to perform a t-test. Furthermore, the critical values provided (e.g., 2.33, 1.96) are more likely to be z-scores, which are used in the context of known population standard deviations, not sample standard deviations.

Therefore, in order to correctly answer Jenny's question, we would require the actual sample size to calculate the t-statistic and compare it against the critical t-value for a one-tailed test at the 1% significance level. Without this information, we cannot complete the hypothesis test to determine the significance of the difference between Jenny's average temperature and the population mean of 98.6°F.

Learn more about t-test here:

https://brainly.com/question/35161872

#SPJ11