High School

The ancient Romans discovered how to make concrete using lime and sand in the ratio of 1:3. How much sand is needed with \(\frac{24}{7}\) units of lime?

A. \(\frac{72}{7}\) units of sand
B. \(\frac{96}{7}\) units of sand
C. 18 units of sand
D. 9 units of sand

Answer :

Final answer:

The correct answer to the amount of sand needed with 24/7 units of lime, using a ratio of 1:3, is 72/7 units of sand (option a). This result is obtained by multiplying the amount of lime (24/7) by 3, following the given lime to sand ratio.

Explanation:

The student is asking about a ratio problem involving mixing lime and sand to make concrete, a Roman building material innovation. To solve the problem, we use the ratio of lime to sand, which is 1:3, to find out how much sand is needed when 24/7 units of lime are used. This is done by multiplying the amount of lime (24/7) by the ratio of sand to lime (3) to get the final amount of sand needed. The calculation would be as follows:

(24/7) × 3 = 72/7

So the correct answer is (a) 72/7 units of sand. This means for every unit of lime, we need three units of sand, and with 24/7 units of lime, we accordingly need 72/7 units of sand.

Learn more about Ratio Problem here:

https://brainly.com/question/28368900

#SPJ11Final answer:

The correct answer to the amount of sand needed with 24/7 units of lime, using a ratio of 1:3, is 72/7 units of sand (option a). This result is obtained by multiplying the amount of lime (24/7) by 3, following the given lime to sand ratio.

Explanation:

The student is asking about a ratio problem involving mixing lime and sand to make concrete, a Roman building material innovation. To solve the problem, we use the ratio of lime to sand, which is 1:3, to find out how much sand is needed when 24/7 units of lime are used. This is done by multiplying the amount of lime (24/7) by the ratio of sand to lime (3) to get the final amount of sand needed. The calculation would be as follows:

(24/7) × 3 = 72/7

So the correct answer is (a) 72/7 units of sand. This means for every unit of lime, we need three units of sand, and with 24/7 units of lime, we accordingly need 72/7 units of sand.