High School

The 21st term of an arithmetic progression (AP) whose first two terms are -3 and 4 is:

A. 17
B. 137
C. 143
D. -143

Answer :

Answer:

(b) 137

Step-by-step explanation:

An arithmetic progression (AP) is a sequence of numbers where the difference between any two consecutive terms is constant. This constant difference is called the common difference.

In this case:

The nth term of an arithmetic progression can be calculated using the following formula:

[tex]\sf t_n = a + (n - 1) \times d [/tex]

where:

  • tn is the nth term of the AP
  • a is the first term of the AP
  • d is the common difference of the AP
  • n is the number of the term

We have,

  • First term (a)= -3
  • The common difference (d)= 7

So, the 21st term can be calculated by substituting given value in above formula:

[tex] \begin{aligned} t_{21 } &\sf = -3 + (21 - 1) \times 7 \\\\ &\sf -3 +20\times 7 \\\\ &\sf = -3+ 140 \\\\ &\sf = 137\end{aligned} [/tex]

Therefore, the answer is (b) 137