Tallula's Home and Garden Inc. packages bird seed. The masses of the bags are known to be normally distributed. A random sample of 103 bags yields an average mass of 12.01 kg with a standard deviation of 0.57 kg.

Find a 98% one-sided lower confidence bound on the true mean mass in kg. Express your answer to three decimal places.

Based on the given sample statistics and a 98% confidence level, we can be 98% confident that the true mean mass of the bird seed bags is at least 11.858 kg.

To find a 98% one-sided lower confidence bound on the true mean mass of the bird seed bags, we can use the formula for a confidence interval for the mean in a normal distribution. However, since we are interested in the lower bound, we need to find the value that leaves only 2% of the distribution to the right.

The formula for the lower confidence bound is:

Lower Bound = Sample Mean - Z * (Sample Standard Deviation / √Sample Size)

Given the values: Sample Mean = 12.01 kg, Sample Standard Deviation (s) = 0.57 kg, Sample Size (n) = 103, and for a 98% confidence level, the Z-value (corresponding to the critical value) is approximately 2.33.

Lower Bound = 12.01 - 2.33 * (0.57 / √103) = 11.858 kg

Interpretation: We are 98% confident that the true mean mass of the bird seed bags is at least 11.858 kg.

To know more about confidence level refer here

brainly.com/question/22851322

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