Answer :
Susie would need 0.8 grams of NaOH to make 100 ml of 0.20 M NaOH solution.
To calculate the grams of NaOH needed to make a 0.20 M NaOH solution, we need to use the equation:
Molarity (M) = moles of solute / volume of solution (in liters)
First, let's convert the given volume of the solution from milliliters (ml) to liters (L):
100 ml = 100/1000 = 0.1 L
Now, we can rearrange the equation to solve for moles of NaOH:
moles of solute = Molarity (M) × volume of solution (in liters)
moles of NaOH = 0.20 M × 0.1 L = 0.02 moles
To convert moles to grams, we need to use the molar mass of NaOH, which is 22.99 g/mol for sodium (Na), 16.00 g/mol for oxygen (O), and 1.01 g/mol for hydrogen (H). Adding these together, we get:
22.99 g/mol (Na) + 16.00 g/mol (O) + 1.01 g/mol (H) = 40.00 g/mol (NaOH)
Finally, we can calculate the grams of NaOH needed:
grams of NaOH = moles of NaOH × molar mass of NaOH
grams of NaOH = 0.02 moles × 40.00 g/mol = 0.8 grams
To know more about NaOH solution refer here:
https://brainly.com/question/14296114
#SPJ11
