Answer :
The angular acceleration of the grindstone is 13.015rad/s².
Tangential force exerted is 182 Newton at a distance of 0.33 m. The mass of the disc is 79 kg the opposing frictional force is of 24 Newton which is exerted distance of 0.7 m from the axis.
We know that the angular acceleration is given by,
A = total net torque/moment of inertia
A is angular acceleration.
Torque = tangential force × distance
Torque by force = 182 x 0.33
Torque by force = 60.06 N-m
Torque by friction = 24 x 0.17
Torque by friction = 4.08 N-m
The net torque = (60.06-4.08)N-m
Moment of inertia of disc = 79(0.33)²/2
Moment of inertia of disc = 4.301 Kg-m²
Now putting all the values,
A = 55.98/4.301
A = 13.015 rad/s²
So, the angular acceleration is 13.015rad/s².
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