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------------------------------------------------ Suppose the scores of seven members of a women's golf team are [tex]$68, 62, 60, 64, 70, 66$[/tex], and [tex]$72$[/tex]. Find the mean, median, and midrange.

a. Mean [tex]$= 64$[/tex], median [tex]$= 64$[/tex], midrange [tex]$= 64$[/tex]
b. Mean [tex]$= 65$[/tex], median [tex]$= 64$[/tex], midrange [tex]$= 66$[/tex]
c. Mean [tex]$= 66$[/tex], median [tex]$= 77$[/tex], midrange [tex]$= 65$[/tex]
d. Mean [tex]$= 66$[/tex], median [tex]$= 66$[/tex], midrange [tex]$= 66$[/tex]

Please select the best answer from the choices provided:
A
B
C
D

Answer :

To solve this, let's find the mean, median, and midrange of the given scores: 68, 62, 60, 64, 70, 66, and 72.

Mean:

1. Add all the scores together:
[tex]\[
68 + 62 + 60 + 64 + 70 + 66 + 72 = 462
\][/tex]
2. Divide the sum by the number of scores to find the mean:
[tex]\[
\frac{462}{7} = 66
\][/tex]

Median:

1. Arrange the scores in ascending order:
60, 62, 64, 66, 68, 70, 72
2. Since there are 7 scores, the median is the middle score, which is the 4th score:
[tex]\[
66
\][/tex]

Midrange:

1. Identify the smallest score, which is 60, and the largest score, which is 72.
2. Calculate the midrange by taking the average of the smallest and largest scores:
[tex]\[
\frac{60 + 72}{2} = 66
\][/tex]

Based on these calculations:
- Mean = 66
- Median = 66
- Midrange = 66

Thus, the correct answer is option D: Mean [tex]\(=66\)[/tex], median [tex]\(=66\)[/tex], midrange [tex]\(=66\)[/tex].