Answer :
Let's solve the compound inequality step-by-step:
The inequality given is:
[tex]\[ -16 \leq x - 11 < -7 \][/tex]
This compound inequality can be broken into two separate inequalities:
1. [tex]\(-16 \leq x - 11\)[/tex]
2. [tex]\(x - 11 < -7\)[/tex]
Let's solve each one separately:
1. Solve [tex]\(-16 \leq x - 11\)[/tex]:
- Add 11 to both sides to isolate [tex]\(x\)[/tex]:
[tex]\[
-16 + 11 \leq x
\][/tex]
[tex]\[
-5 \leq x
\][/tex]
So, [tex]\(x \geq -5\)[/tex].
2. Solve [tex]\(x - 11 < -7\)[/tex]:
- Add 11 to both sides to isolate [tex]\(x\)[/tex]:
[tex]\[
x - 11 + 11 < -7 + 11
\][/tex]
[tex]\[
x < 4
\][/tex]
Now, combine the solutions from both inequalities:
From the first inequality, we have [tex]\(x \geq -5\)[/tex], and from the second inequality, we have [tex]\(x < 4\)[/tex].
Therefore, the solution to the compound inequality [tex]\(-16 \leq x - 11 < -7\)[/tex] is:
[tex]\[
-5 \leq x < 4
\][/tex]
This means that [tex]\(x\)[/tex] can be any number greater than or equal to [tex]\(-5\)[/tex] and less than 4.
The inequality given is:
[tex]\[ -16 \leq x - 11 < -7 \][/tex]
This compound inequality can be broken into two separate inequalities:
1. [tex]\(-16 \leq x - 11\)[/tex]
2. [tex]\(x - 11 < -7\)[/tex]
Let's solve each one separately:
1. Solve [tex]\(-16 \leq x - 11\)[/tex]:
- Add 11 to both sides to isolate [tex]\(x\)[/tex]:
[tex]\[
-16 + 11 \leq x
\][/tex]
[tex]\[
-5 \leq x
\][/tex]
So, [tex]\(x \geq -5\)[/tex].
2. Solve [tex]\(x - 11 < -7\)[/tex]:
- Add 11 to both sides to isolate [tex]\(x\)[/tex]:
[tex]\[
x - 11 + 11 < -7 + 11
\][/tex]
[tex]\[
x < 4
\][/tex]
Now, combine the solutions from both inequalities:
From the first inequality, we have [tex]\(x \geq -5\)[/tex], and from the second inequality, we have [tex]\(x < 4\)[/tex].
Therefore, the solution to the compound inequality [tex]\(-16 \leq x - 11 < -7\)[/tex] is:
[tex]\[
-5 \leq x < 4
\][/tex]
This means that [tex]\(x\)[/tex] can be any number greater than or equal to [tex]\(-5\)[/tex] and less than 4.