Answer :
Final answer:
To solve the quadratic equation 48x^3+40x^2−x−3=0 given that -3/4 is a zero, we can use synthetic division and the quadratic formula to find the solutions which are x = 1/6 and x = 4/3.
Explanation:
To solve the equation 48x^3+40x^2−x−3=0 given that -3/4 is a zero, we can first use synthetic division to divide the equation by x + 3/4.
This will give us a new equation: 48x^2 - 25x + 4 = 0.
We can then factor the quadratic equation or use the quadratic formula to solve for x.
Using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a), we can substitute the values a = 48, b = -25, and c = 4 into the formula to find the values of x.
After solving the quadratic equation, we find the values of x to be x = 1/6 and x = 4/3.
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