Solve for the unknown \( PR \).

Given:

\[
\frac{QR}{EH} = \frac{PQ}{FG} = \frac{PR}{FH}
\]

\[
\frac{12}{8} = \frac{6}{4} = \frac{x}{10}
\]

Solve:

\[
\frac{6}{4} = \frac{x}{10}
\]

Cross-multiply to solve for \( x \):

\[
6 \times 10 = 4 \times x
\]

\[
60 = 4x
\]

\[
x = \frac{60}{4}
\]

\[
x = 15
\]

Therefore, \( PR = 15 \).

To solve for the unknown PR, we can use the fact that the ratio QR/EH is equal to the ratio PQ/FG, which is also equal to the ratio PR/FH. In this case, we are given that QR/EH is 12/8, PQ/FG is 6/4, and PR/FH is x/10. To find the value of x, we can set up a proportion:

QR/EH = PQ/FG = PR/FH

12/8 = 6/4 = x/10

Cross multiplying, we get:

12 * 10 = 8 * x

120 = 8x

Dividing both sides by 8, we find that x = 15.

Solve for the unknown \( PR \).Given:\[\frac{QR}{EH} = \frac{PQ}{FG} = \frac{PR}{FH}\]\[\frac{12}{8} = \frac{6}{4} = \frac{x}{10}\]Solve:\[\frac{6}{4} = \frac{x}{10}\]Cross-multiply to solve for \( x \):\[6 \times 10 = 4 \times x\]\[60 = 4x\]\[x = \frac{60}{4}\]\[x = 15\]Therefore, \( PR = 15 \).

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