Select the correct answer.

The product of two integers is [tex]112[/tex]. One number is four more than three times the other. Which of the following equations could be used to find one of the numbers?

A. [tex]3x^2 + 4x = 112[/tex]
B. [tex]3x^2 + 4 = 112[/tex]
C. [tex]4x^2 + 3x = 112[/tex]
D. [tex]4x^2 + 3 = 112[/tex]

Let's carefully go through the given problem step-by-step to find one of the numbers.

### Problem Statement:
The product of two integers is 112. One number is four more than three times the other.

### Setting up the Equations:
1. Let [tex]$ x $[/tex] be one of the numbers.
2. The other number then can be written as [tex]$ 3x + 4 $[/tex], because it is four more than three times [tex]$ x $[/tex].

### Using the Information:
The product of the two numbers is given as 112. Therefore, we can set up the following equation:
[tex]\[ x \cdot (3x + 4) = 112 \][/tex]

### Simplifying the Equation:
Now, we distribute [tex]$ x $[/tex] across the term in the parenthesis:
[tex]\[ x \cdot 3x + x \cdot 4 = 112 \][/tex]
[tex]\[ 3x^2 + 4x = 112 \][/tex]

### Formulating the Equation:
We now have the quadratic equation in the form:
[tex]\[ 3x^2 + 4x = 112 \][/tex]

Among the choices given:
- A. [tex]$ 3x^2 + 4x = 112 $[/tex] aligns with our derived equation.

So, the correct equation that could be used to find one of the numbers is answer choice:

### Answer:
[tex]\[ \boxed{A} \][/tex]