Select the correct answer from each drop-down menu.

If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]\square[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\square[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Sure, let's go through the process step by step.

First, let's look at the mating between a heterozygous male with the genotype Ww and a homozygous recessive female with the genotype ww.

### Punnett Square for Ww x ww:

```
W | w
----------------
w | Ww | ww
----------------
w | Ww | ww
```

In this Punnett square:

- There are 2 Ww combinations.
- There are 2 ww combinations.

Out of the 4 total offspring:

- 2 are heterozygous (Ww).

So, the probability of having a heterozygous offspring (Ww) is [tex]\(\frac{2}{4} = 0.5\)[/tex] or 50%.

---

Next, let's look at the cross between a heterozygous Ww and a homozygous dominant WW.

### Punnett Square for Ww x WW:

```
W | w
----------------
W | WW | Ww
----------------
W | WW | Ww
```

In this Punnett square:

- There are 2 WW combinations.
- There are 2 Ww combinations.
- There are no ww combinations.

So, the probability of having a homozygous recessive offspring (ww) is 0.

I hope this helps! If you have any more questions, feel free to ask.