Select the correct answer from each drop-down menu.

If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that [tex]$\square$[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is [tex]$\square$[/tex].

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Sure! Let's solve the question step by step.

Part 1: Probability of Heterozygous Offspring (Ww x ww)

1. Setting up the Cross:
- We have a heterozygous male with genotype Ww.
- We have a homozygous recessive female with genotype ww.

2. Punnett Square for Ww x ww:

```
| W | w |
------------
w | Ww | ww |
------------
w | Ww | ww |
```

3. Analyzing the Offspring:
- The possible genotypes of the offspring are Ww and ww.
- There are 2 Ww (heterozygous) offspring and 2 ww (homozygous recessive) offspring.

4. Calculating the Probability:
- The probability of getting a heterozygous (Ww) offspring is 2 out of 4 possibilities, which is 2/4 = 0.5 or 50%.

Part 2: Probability of Homozygous Recessive Offspring (WW x WW)

1. Setting up the Cross:
- We cross a heterozygous WW (this looks like a typo in the original text and should actually read heterozygous Ww) with a homozygous dominant WW.

2. Punnett Square for WW x WW (assuming the typo was meant to be considered):

```
| W | W |
------------
W | WW | WW |
------------
W | WW | WW |
```

3. Analyzing the Offspring:
- All possible outcomes are WW (homozygous dominant) offspring.

4. Calculating the Probability:
- Since there are no ww (homozygous recessive) offspring in any of these combinations, the probability of having a homozygous recessive offspring is 0.

In conclusion:
- The chance that an offspring will be heterozygous (Ww) from the first cross is 50%.
- The probability of having a homozygous recessive offspring from the second cross is 0.