Answer :
To solve this problem, we need to understand how to use a Punnett square to determine the probabilities of different genotypes in the offspring.
1. Heterozygous male (Ww) crossed with homozygous recessive female (ww):
- Set up the Punnett square:
[tex]\[
\begin{array}{c|c c}
& w & w \\
\hline
W & Ww & Ww \\
w & ww & ww \\
\end{array}
\][/tex]
- The possible genotypes of the offspring are: Ww, Ww, ww, ww.
- Count the heterozygous offspring (genotype Ww): There are 2 Ww combinations.
- Total number of offspring types is 4 (Ww, Ww, ww, ww).
- Probability of heterozygous offspring: [tex]\(\frac{2}{4} = 0.5\)[/tex].
2. Heterozygous (Ww) crossed with homozygous dominant (WW):
- Set up the Punnett square:
[tex]\[
\begin{array}{c|c c}
& W & W \\
\hline
W & WW & WW \\
w & Ww & Ww \\
\end{array}
\][/tex]
- The possible genotypes of the offspring are: WW, WW, Ww, Ww.
- Count the homozygous recessive offspring (genotype ww): There are 0 ww combinations.
- Total number of offspring types is 4 (WW, WW, Ww, Ww).
- Probability of homozygous recessive offspring is: [tex]\(\frac{0}{4} = 0.0\)[/tex].
Therefore, there is a 50% chance that the offspring will be heterozygous when a heterozygous male is crossed with a homozygous recessive female, and there is a 0% chance of having a homozygous recessive offspring when a heterozygous individual is crossed with a homozygous dominant individual.
1. Heterozygous male (Ww) crossed with homozygous recessive female (ww):
- Set up the Punnett square:
[tex]\[
\begin{array}{c|c c}
& w & w \\
\hline
W & Ww & Ww \\
w & ww & ww \\
\end{array}
\][/tex]
- The possible genotypes of the offspring are: Ww, Ww, ww, ww.
- Count the heterozygous offspring (genotype Ww): There are 2 Ww combinations.
- Total number of offspring types is 4 (Ww, Ww, ww, ww).
- Probability of heterozygous offspring: [tex]\(\frac{2}{4} = 0.5\)[/tex].
2. Heterozygous (Ww) crossed with homozygous dominant (WW):
- Set up the Punnett square:
[tex]\[
\begin{array}{c|c c}
& W & W \\
\hline
W & WW & WW \\
w & Ww & Ww \\
\end{array}
\][/tex]
- The possible genotypes of the offspring are: WW, WW, Ww, Ww.
- Count the homozygous recessive offspring (genotype ww): There are 0 ww combinations.
- Total number of offspring types is 4 (WW, WW, Ww, Ww).
- Probability of homozygous recessive offspring is: [tex]\(\frac{0}{4} = 0.0\)[/tex].
Therefore, there is a 50% chance that the offspring will be heterozygous when a heterozygous male is crossed with a homozygous recessive female, and there is a 0% chance of having a homozygous recessive offspring when a heterozygous individual is crossed with a homozygous dominant individual.
