Select the correct answer from each drop-down menu.

If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that:

[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\][/tex]

If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is:

[tex]$\square$[/tex]

[tex]\[
\begin{array}{|c|c|c|}
\hline
& W & W \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\][/tex]

Let's solve the question step-by-step:

1. First Scenario: Heterozygous Male (Ww) with Homozygous Recessive Female (ww)
- We have a male with genotype Ww and a female with genotype ww.

- To find the possible offspring genotypes, we set up a Punnett Square:
```
W w
w Ww ww
w Ww ww
```

- From this Punnett Square, we get:
- 2 out of 4 squares are Ww (heterozygous).
- 2 out of 4 squares are ww (homozygous recessive).

- Therefore, there is a 50% chance (2 out of 4) for having a heterozygous offspring (Ww).

2. Second Scenario: Heterozygous Male (Ww) with Homozygous Dominant Female (WW)
- We have a male with genotype Ww and a female with genotype WW.

- Let's set up a Punnett Square for this cross:
```
W W
W WW WW
w Ww Ww
```

- From this Punnett Square, we can see that:
- 4 out of 4 squares have either WW or Ww genotype.
- None of the squares have the ww genotype.

- Thus, the probability of having a homozygous recessive offspring (ww) is 0% (0 out of 4).

To summarize:
- In the first scenario, there is a 50% chance of having a heterozygous offspring (Ww).
- In the second scenario, there is a 0% chance of having a homozygous recessive offspring (ww).