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If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]\square[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{tabular}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{tabular}
\]
[/tex]

Sure! Let's solve this genetics problem step-by-step.

1. Understand the Genotypes:
- We have a heterozygous male with the genotype Ww.
- We have a homozygous recessive female with the genotype ww.

2. Set up a Punnett Square:
- The male can produce gametes with either W or w.
- The female can produce gametes with w only.

3. Fill the Punnett Square:

| | W | w |
|--------|----|----|
| w | Ww | ww |
| w | Ww | ww |

- The Punnett square shows all the possible genotypes of the offspring.
- From the square:
- One offspring could be Ww (top row, left cell).
- Another could be ww (top row, right cell).
- Another could be Ww (bottom row, left cell).
- And another could be ww (bottom row, right cell).

4. Determine the Probability:
- There are 4 possible outcomes (as seen in the Punnett square).
- Count the heterozygous genotype (Ww) among the offspring:
- There are 2 Ww outcomes.

5. Calculate the Probability:
- To find the probability of having heterozygous offspring (Ww), divide the number of heterozygous outcomes by the total number of outcomes:
- Probability = Number of Ww outcomes / Total outcomes = 2 / 4 = 0.5

Hence, there is a 0.5 (or 50%) chance that the offspring will be heterozygous.