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If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 50% chance that the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0%.

[tex]
\[
\begin{array}{|c|c|c|}
\hline & W & W \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Let's analyze each genetic cross step-by-step.

### First Situation: Heterozygous male (Ww) × Homozygous recessive female (ww)

1. Parental Genotypes:
- Male: Ww (one dominant allele 'W' and one recessive allele 'w')
- Female: ww (two recessive alleles 'w')

2. Possible Gametes:
- Male can pass on either 'W' or 'w'.
- Female can only pass on 'w'.

3. Punnett Square Setup:
- The top row will have the male gametes: W and w.
- The side column will have the female gamete: both w and w (since both are the same).

```
| W | w |
w | Ww | ww |
w | Ww | ww |
```

4. Punnett Square Results:
- Two squares (Ww) represent heterozygous offspring.
- Two squares (ww) represent homozygous recessive offspring.

5. Probability Calculation:
- Out of 4 possible outcomes, 2 are heterozygous (Ww).
- Probability of heterozygous offspring is 2/4 or 0.5 (50%).

### Second Situation: Heterozygous (Ww) × Homozygous dominant (WW)

1. Parental Genotypes:
- One parent is Ww (heterozygous).
- The other parent is WW (homozygous dominant).

2. Possible Gametes:
- The heterozygous parent can pass on either 'W' or 'w'.
- The homozygous dominant parent can only pass on 'W'.

3. Punnett Square Setup:
- The top row will have the gametes from the homozygous dominant parent: W and W.
- The side column will have the gametes from the heterozygous parent: W and w.

```
| W | W |
W | WW | WW |
w | Ww | Ww |
```

4. Punnett Square Results:
- All squares show offspring with at least one 'W', either WW or Ww.
- There are no squares with both recessive alleles (ww).

5. Probability Calculation:
- Probability of having a homozygous recessive offspring (ww) is 0 out of 4.
- Probability is 0 or 0.0 (0%).

These detailed steps illustrate the probability outcomes for each genetic cross.