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If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that the offspring will be heterozygous.

[tex]
\[
\begin{tabular}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{tabular}
\]
[/tex]

If the heterozygous Ww is crossed with a homozygous dominant WW, then the probability of having a homozygous recessive offspring is:

[tex]
\[
\begin{tabular}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{tabular}
\]
[/tex]

Let's take a look at both genetic crosses to determine the probabilities of the offspring's genotypes.

First Cross:

- Genotypes involved: Heterozygous male (Ww) and homozygous recessive female (ww).

- Punnett Square for Ww x ww:
```
| W | w |
---------------
w | Ww | ww |
---------------
w | Ww | ww |
```

- Possible Offspring:
- Ww (heterozygous)
- ww (homozygous recessive)

- Probability of being heterozygous (Ww):
- Out of 4 possible outcomes, there are 2 Ww combinations.
- Probability = 2/4 = 0.5, or 50%.

Second Cross:

- Genotypes involved: Heterozygous individual (Ww) with a homozygous dominant individual (WW).

- Punnett Square for Ww x WW:
```
| W | w |
---------------
W | WW | Ww |
---------------
W | WW | Ww |
```

- Possible Offspring:
- WW (homozygous dominant)
- Ww (heterozygous)

- Probability of being homozygous recessive (ww):
- There are no ww combinations among the outcomes.
- Probability = 0, or 0%.

In summary, when a heterozygous male (Ww) mates with a homozygous recessive female (ww), there is a 50% chance of producing heterozygous (Ww) offspring. When a heterozygous individual (Ww) is crossed with a homozygous dominant individual (WW), the probability of having a homozygous recessive (ww) offspring is 0%.