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If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that:

[tex]
\[
\begin{array}{|c|c|c|}
\hline
\multicolumn{3}{|c|}{\text{\checkmark of the offspring will be heterozygous.}} \\
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is:

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & \\
\hline
W & WW & Ww \\
\hline
W & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Let's break down the genetics question step-by-step:

1. First Scenario: Heterozygous Male (Ww) x Homozygous Recessive Female (ww)
- We're dealing with two genotypes: Ww and ww.
- When you create a Punnett square, you place the alleles of one parent along the top (W and w) and alleles of the other parent along the side (w and w).
- By filling in the square, you get the potential genetic combinations of the offspring:
- Top row: Ww and ww
- Bottom row: Ww and ww
- So, there are 4 possible outcomes: Ww, ww, Ww, ww.
- The question asks for the probability that offspring will be heterozygous (Ww).
- In this case, 2 out of the 4 possible offspring are Ww.
- Therefore, the chance of offspring being heterozygous is 2/4, which simplifies to 0.5 or 50%.

2. Second Scenario: Heterozygous (Ww) x Homozygous Dominant (WW)
- Here, the genotypes are Ww and WW.
- In the Punnett square, you place W and w along one side and W and W along the other.
- Fill out the square to find these combinations:
- Top row: WW and WW
- Bottom row: Ww and Ww
- Again, you have 4 possible outcomes: WW, WW, Ww, Ww.
- This time, the question asks about the probability of having homozygous recessive offspring. A homozygous recessive genotype is ww.
- None of the offspring in this scenario are ww.
- Thus, the probability of having a homozygous recessive offspring is 0/4, which is 0.0 or 0%.

In summary, there's a 50% chance the offspring will be heterozygous (Ww) in the first case and a 0% chance of having a homozygous recessive (ww) offspring in the second case.