Answer :
Answer:
The probability that a randomly selected resident owns a
✔ cat
, given that the person also owns a
✔ dog
, is equal to approximately
✔ 0.90
.
Step-by-step explanation:
Just did it on edge.
Next slide answer is:
The probability that a randomly selected resident owns a
✔ dog
, given that the person also owns a
✔ cat
, is equal to approximately
✔ 0.519
.
Final answer:
When we randomly select a resident who owns a dog, there's a 90% chance that this resident also owns a cat.
Explanation:
The given table shows the distribution of pets in an apartment building. We are looking to find P(A|B), where event A is owning a cat, and event B is owning a dog. This probability indicates the chance that a randomly selected resident owns a cat, given that they already own a dog. We find this by dividing the number of residents who own both a dog and a cat by the total number of residents who own a dog.
From the given table, we know that 27 residents own both a cat and a dog. Whereas, 30 residents own a dog (regardless of whether or not they also own a cat). Hence, P(A|B) can be calculated as follows:
P(A|B) = Number of residents owning both a cat and a dog / Total number of residents owning a dog
= 27/30 = 0.9
Therefore, given that a resident owns a dog, the probability that they also own a cat is 0.9 or 90%.
Learn more about Probability here:
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