Answer :
Let's go through the question step by step:
1. First Scenario: Heterozygous Male (Ww) and Homozygous Recessive Female (ww)
- The male has a genotype of Ww, meaning he has one dominant gene (W) and one recessive gene (w).
- The female has a genotype of ww, meaning she has two recessive genes.
When they are mated, the possible combinations for their offspring are as follows:
- W from the male and w from the female = Ww
- w from the male and w from the female = ww
Since there are two sperm possibilities (W and w) and two egg possibilities (both w), the potential genotype combinations for the offspring are:
- Ww (heterozygous)
- Ww (heterozygous)
- ww (homozygous recessive)
- ww (homozygous recessive)
Of these combinations, two are heterozygous (Ww). So, the probability of an offspring being heterozygous is:
[tex]\(\frac{2}{4} = 0.5\)[/tex]
2. Second Scenario: Heterozygous (Ww) and Homozygous Dominant (WW)
- One parent has a genotype of Ww (heterozygous).
- The other parent has a genotype of WW (homozygous dominant).
The possible combinations for their offspring are:
- W from the Ww parent and W from the WW parent = WW
- w from the Ww parent and W from the WW parent = Ww
Since there are two gene contributions from the heterozygous parent (W and w) and only one contribution from the homozygous dominant parent (both W), the potential genotype combinations are:
- WW (homozygous dominant)
- WW (homozygous dominant)
- Ww (heterozygous)
- Ww (heterozygous)
In this scenario, there are no combinations resulting in homozygous recessive (ww) offspring. Therefore, the probability of having a homozygous recessive offspring is:
[tex]\(0\)[/tex]
So, the chance that an offspring will be heterozygous in the first scenario is 0.5, and the probability of having a homozygous recessive offspring in the second scenario is 0.0.
1. First Scenario: Heterozygous Male (Ww) and Homozygous Recessive Female (ww)
- The male has a genotype of Ww, meaning he has one dominant gene (W) and one recessive gene (w).
- The female has a genotype of ww, meaning she has two recessive genes.
When they are mated, the possible combinations for their offspring are as follows:
- W from the male and w from the female = Ww
- w from the male and w from the female = ww
Since there are two sperm possibilities (W and w) and two egg possibilities (both w), the potential genotype combinations for the offspring are:
- Ww (heterozygous)
- Ww (heterozygous)
- ww (homozygous recessive)
- ww (homozygous recessive)
Of these combinations, two are heterozygous (Ww). So, the probability of an offspring being heterozygous is:
[tex]\(\frac{2}{4} = 0.5\)[/tex]
2. Second Scenario: Heterozygous (Ww) and Homozygous Dominant (WW)
- One parent has a genotype of Ww (heterozygous).
- The other parent has a genotype of WW (homozygous dominant).
The possible combinations for their offspring are:
- W from the Ww parent and W from the WW parent = WW
- w from the Ww parent and W from the WW parent = Ww
Since there are two gene contributions from the heterozygous parent (W and w) and only one contribution from the homozygous dominant parent (both W), the potential genotype combinations are:
- WW (homozygous dominant)
- WW (homozygous dominant)
- Ww (heterozygous)
- Ww (heterozygous)
In this scenario, there are no combinations resulting in homozygous recessive (ww) offspring. Therefore, the probability of having a homozygous recessive offspring is:
[tex]\(0\)[/tex]
So, the chance that an offspring will be heterozygous in the first scenario is 0.5, and the probability of having a homozygous recessive offspring in the second scenario is 0.0.
