Answer :
Let's solve the question using genetic principles.
### Part 1: Heterozygous Offspring Probability
1. Genotypes of Parents:
- Male: Ww (heterozygous)
- Female: ww (homozygous recessive)
2. Possible Offspring Genotypes:
- You can determine the possible offspring genotypes by pairing each allele from the male with each allele from the female:
- W (from male) with w (from female) gives Ww
- w (from male) with w (from female) gives ww
3. Punnett Square:
- The Punnett square for this cross is:
| | w | w |
|-------|---|---|
| W | Ww | Ww |
| w | ww | ww |
- This results in:
- 2 squares with Ww (heterozygous)
- 2 squares with ww (homozygous recessive)
4. Probability of Heterozygous Offspring:
- There are 4 possible outcomes, with 2 of them being Ww.
- Thus, the probability is 2 out of 4, which is 0.5 or 50%.
### Part 2: Homozygous Recessive Offspring Probability
1. Genotypes of Parents:
- Male: Ww (heterozygous)
- Female: WW (homozygous dominant)
2. Possible Offspring Genotypes:
- You can pair each allele from the male with each allele from the female to form the offspring:
- W (from male) with W (from female) gives WW
- w (from male) with W (from female) gives Ww
3. Punnett Square:
- The Punnett square for this cross is:
| | W | W |
|-------|---|---|
| W | WW | WW |
| w | Ww | Ww |
- This results in:
- 2 squares with WW (homozygous dominant)
- 2 squares with Ww (heterozygous)
4. Probability of Homozygous Recessive Offspring:
- None of the offspring are ww, as the W allele is always present.
- Therefore, the probability of having homozygous recessive offspring is 0.0 or 0%.
In summary, the chance of the offspring being heterozygous when crossing a heterozygous male and a homozygous recessive female is 0.5, and the probability of having homozygous recessive offspring when crossing a heterozygous male and a homozygous dominant female is 0.0.
### Part 1: Heterozygous Offspring Probability
1. Genotypes of Parents:
- Male: Ww (heterozygous)
- Female: ww (homozygous recessive)
2. Possible Offspring Genotypes:
- You can determine the possible offspring genotypes by pairing each allele from the male with each allele from the female:
- W (from male) with w (from female) gives Ww
- w (from male) with w (from female) gives ww
3. Punnett Square:
- The Punnett square for this cross is:
| | w | w |
|-------|---|---|
| W | Ww | Ww |
| w | ww | ww |
- This results in:
- 2 squares with Ww (heterozygous)
- 2 squares with ww (homozygous recessive)
4. Probability of Heterozygous Offspring:
- There are 4 possible outcomes, with 2 of them being Ww.
- Thus, the probability is 2 out of 4, which is 0.5 or 50%.
### Part 2: Homozygous Recessive Offspring Probability
1. Genotypes of Parents:
- Male: Ww (heterozygous)
- Female: WW (homozygous dominant)
2. Possible Offspring Genotypes:
- You can pair each allele from the male with each allele from the female to form the offspring:
- W (from male) with W (from female) gives WW
- w (from male) with W (from female) gives Ww
3. Punnett Square:
- The Punnett square for this cross is:
| | W | W |
|-------|---|---|
| W | WW | WW |
| w | Ww | Ww |
- This results in:
- 2 squares with WW (homozygous dominant)
- 2 squares with Ww (heterozygous)
4. Probability of Homozygous Recessive Offspring:
- None of the offspring are ww, as the W allele is always present.
- Therefore, the probability of having homozygous recessive offspring is 0.0 or 0%.
In summary, the chance of the offspring being heterozygous when crossing a heterozygous male and a homozygous recessive female is 0.5, and the probability of having homozygous recessive offspring when crossing a heterozygous male and a homozygous dominant female is 0.0.
