Answer :
Sure! Let's solve the problem step-by-step.
### Problem 1:
We're crossing a heterozygous male (Ww) with a homozygous recessive female (ww).
- Parents' Genotypes:
- Male: Ww
- Female: ww
To find the possible genotypes of the offspring, we can use a Punnett square. Here, we'll pair each allele from the male with each allele from the female:
```
| W | w
---------------
w | Ww | ww
---------------
w | Ww | ww
---------------
```
Possible Offspring Genotypes:
- 2 offspring with Ww
- 2 offspring with ww
This gives us a total of 4 possible combinations. Out of these, 2 are heterozygous (Ww).
- Probability of Heterozygous Offspring (Ww):
[tex]\[
\frac{\text{Number of Ww}}{\text{Total Offspring}} = \frac{2}{4} = 0.5
\][/tex]
So, there is a 0.5 chance that the offspring will be heterozygous.
### Problem 2:
Now, we cross a heterozygous (Ww) with a homozygous dominant (WW).
- Parents' Genotypes:
- One Parent: Ww
- Other Parent: WW
Again, we use a Punnett square:
```
| W | W
---------------
W | WW | WW
---------------
w | Ww | Ww
---------------
```
Possible Offspring Genotypes:
- 2 offspring with WW
- 2 offspring with Ww
Here, all the offspring will be either WW or Ww. None will be homozygous recessive (ww).
- Probability of Homozygous Recessive Offspring (ww):
[tex]\[
\frac{\text{Number of ww}}{\text{Total Offspring}} = \frac{0}{4} = 0.0
\][/tex]
Thus, there is a 0.0 chance of having homozygous recessive offspring.
I hope this helps you understand how to determine the probabilities of different genotypes using Punnett squares! If you have any further questions, feel free to ask.
### Problem 1:
We're crossing a heterozygous male (Ww) with a homozygous recessive female (ww).
- Parents' Genotypes:
- Male: Ww
- Female: ww
To find the possible genotypes of the offspring, we can use a Punnett square. Here, we'll pair each allele from the male with each allele from the female:
```
| W | w
---------------
w | Ww | ww
---------------
w | Ww | ww
---------------
```
Possible Offspring Genotypes:
- 2 offspring with Ww
- 2 offspring with ww
This gives us a total of 4 possible combinations. Out of these, 2 are heterozygous (Ww).
- Probability of Heterozygous Offspring (Ww):
[tex]\[
\frac{\text{Number of Ww}}{\text{Total Offspring}} = \frac{2}{4} = 0.5
\][/tex]
So, there is a 0.5 chance that the offspring will be heterozygous.
### Problem 2:
Now, we cross a heterozygous (Ww) with a homozygous dominant (WW).
- Parents' Genotypes:
- One Parent: Ww
- Other Parent: WW
Again, we use a Punnett square:
```
| W | W
---------------
W | WW | WW
---------------
w | Ww | Ww
---------------
```
Possible Offspring Genotypes:
- 2 offspring with WW
- 2 offspring with Ww
Here, all the offspring will be either WW or Ww. None will be homozygous recessive (ww).
- Probability of Homozygous Recessive Offspring (ww):
[tex]\[
\frac{\text{Number of ww}}{\text{Total Offspring}} = \frac{0}{4} = 0.0
\][/tex]
Thus, there is a 0.0 chance of having homozygous recessive offspring.
I hope this helps you understand how to determine the probabilities of different genotypes using Punnett squares! If you have any further questions, feel free to ask.
