Answer :
Let's work through each part of the question step-by-step:
### Part 1
We are looking at a genetic cross between a heterozygous male (Ww) and a homozygous recessive female (ww). The question asks us what fraction of their offspring will be heterozygous.
1. Determine the possible gametes:
- The male (Ww) can produce gametes with either the W allele or the w allele.
- The female (ww) can only produce gametes with the w allele.
2. Set up the Punnett square:
| | W | w |
|---------|-----|-----|
| w | Ww | ww |
| w | Ww | ww |
3. Analyze the offspring:
- Out of the four possible combinations:
- Two will be Ww (heterozygous).
- Two will be ww (homozygous recessive).
4. Calculate probability:
- The probability of the offspring being heterozygous (Ww) is 2 out of 4, or 0.5 (50%).
### Part 2
Next, we examine the cross between two individuals. The genotype mentioned in the question seems incorrect because "heterozygous, WW" is not possible. However, typically this part of the question deals with crossing WW with another genotype. Let's assume the typo might have meant a different cross but based on typical understanding:
1. Consider the cross, possibly intended between homozygous dominant (WW) and homozygous recessive (ww).
2. Set up the potential Punnett square for a reasonable scenario:
| | W | W |
|--------|-----|-----|
| w | Ww | Ww |
| w | Ww | Ww |
3. Analyze the offspring:
- All offspring (4 out of 4 possibilities) will be Ww (heterozygous).
- No offspring will be ww (homozygous recessive).
4. Calculate the probability:
- The probability of having homozygous recessive offspring (ww) is 0 out of 4, or 0.0 (0%).
In summary:
- For the first part, the chance that the offspring will be heterozygous is 0.5 (50%).
- For the second part, the probability of having a homozygous recessive offspring is 0.0 (0%).
### Part 1
We are looking at a genetic cross between a heterozygous male (Ww) and a homozygous recessive female (ww). The question asks us what fraction of their offspring will be heterozygous.
1. Determine the possible gametes:
- The male (Ww) can produce gametes with either the W allele or the w allele.
- The female (ww) can only produce gametes with the w allele.
2. Set up the Punnett square:
| | W | w |
|---------|-----|-----|
| w | Ww | ww |
| w | Ww | ww |
3. Analyze the offspring:
- Out of the four possible combinations:
- Two will be Ww (heterozygous).
- Two will be ww (homozygous recessive).
4. Calculate probability:
- The probability of the offspring being heterozygous (Ww) is 2 out of 4, or 0.5 (50%).
### Part 2
Next, we examine the cross between two individuals. The genotype mentioned in the question seems incorrect because "heterozygous, WW" is not possible. However, typically this part of the question deals with crossing WW with another genotype. Let's assume the typo might have meant a different cross but based on typical understanding:
1. Consider the cross, possibly intended between homozygous dominant (WW) and homozygous recessive (ww).
2. Set up the potential Punnett square for a reasonable scenario:
| | W | W |
|--------|-----|-----|
| w | Ww | Ww |
| w | Ww | Ww |
3. Analyze the offspring:
- All offspring (4 out of 4 possibilities) will be Ww (heterozygous).
- No offspring will be ww (homozygous recessive).
4. Calculate the probability:
- The probability of having homozygous recessive offspring (ww) is 0 out of 4, or 0.0 (0%).
In summary:
- For the first part, the chance that the offspring will be heterozygous is 0.5 (50%).
- For the second part, the probability of having a homozygous recessive offspring is 0.0 (0%).
