Answer :
The gravitational force experienced by a 50 kg box moving down a 60-degree inclined plane is the component of its weight acting along the plane, which is approximately 424 N. so the correct option is d. 424 N
The question concerns the gravitational force experienced by a 50 kg box moving down a frictionless plane inclined at a 60-degree angle. To calculate the force, one needs to consider the component of gravitational force acting along the incline. The full gravitational force acting on the box would be Fg = m*g, where m is the mass and g is the acceleration due to gravity (9.8 m/s2). So for a 50 kg box, the total gravitational force is Fg = 50 kg * 9.8 m/s2 = 490 N. However, only a component of this force acts along the inclined plane, which is Fg * sin(θ), with θ being the angle of the incline. So the force along the plane is 490 N * sin(60°) which equals 490 N * (sqrt(3)/2), resulting in approximately 424.3 N, which we round off to 424 N for the purpose of this question. so the correct option is d. 424 N
