Answer :
Sure, let's break down the given genetic crosses in detail to understand the probabilities of the offspring having certain genotypes.
### First Scenario:
A heterozygous male (genotype Ww) is mated with a homozygous recessive female (genotype ww).
Here is the Punnett square for this cross:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
From the Punnett square:
- There are 2 outcomes of Ww.
- There are 2 outcomes of ww.
Therefore, out of 4 possible outcomes:
- The probability of having a heterozygous (Ww) offspring is 2 out of 4, which simplifies to 50%.
### Second Scenario:
A heterozygous (Ww) individual is crossed with a homozygous dominant (WW) individual.
Here is the Punnett square for this cross:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\][/tex]
From the Punnett square:
- There are 2 outcomes of WW.
- There are 2 outcomes of Ww.
- There are 0 outcomes of ww.
Hence, the probability of having a homozygous recessive (ww) offspring is 0%.
### Correct Answers to the Drop-Down Menus:
1. If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 50% chance that the offspring will be heterozygous.
2. If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0%.
### First Scenario:
A heterozygous male (genotype Ww) is mated with a homozygous recessive female (genotype ww).
Here is the Punnett square for this cross:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{array}
\][/tex]
From the Punnett square:
- There are 2 outcomes of Ww.
- There are 2 outcomes of ww.
Therefore, out of 4 possible outcomes:
- The probability of having a heterozygous (Ww) offspring is 2 out of 4, which simplifies to 50%.
### Second Scenario:
A heterozygous (Ww) individual is crossed with a homozygous dominant (WW) individual.
Here is the Punnett square for this cross:
[tex]\[
\begin{array}{|c|c|c|}
\hline & W & w \\
\hline W & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{array}
\][/tex]
From the Punnett square:
- There are 2 outcomes of WW.
- There are 2 outcomes of Ww.
- There are 0 outcomes of ww.
Hence, the probability of having a homozygous recessive (ww) offspring is 0%.
### Correct Answers to the Drop-Down Menus:
1. If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 50% chance that the offspring will be heterozygous.
2. If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0%.