Select the correct answer.

A restaurant has a total of 60 tables. Of those tables, 38 are round, and 13 are located by the window. There are 6 round tables by the window. If tables are randomly assigned to customers, what is the probability that a customer will be seated at a round table or by the window?

A. [tex]\frac{47}{60}[/tex]
B. [tex]\frac{29}{60}[/tex]
C. [tex]\frac{45}{60}[/tex]
D. [tex]\frac{41}{60}[/tex]

We start by noting the following:

- The total number of tables is [tex]$60$[/tex].
- There are [tex]$38$[/tex] round tables.
- There are [tex]$13$[/tex] tables by the window.
- Among these, [tex]$6$[/tex] tables are both round and by the window.

To find the number of tables that are either round or by the window, we use the inclusion-exclusion principle. This principle tells us that the total in the union is given by

[tex]$$
\text{Union} = \text{Round} + \text{Window} - \text{Both}.
$$[/tex]

Substituting the given numbers, we have

[tex]$$
\text{Union} = 38 + 13 - 6 = 45.
$$[/tex]

Thus, there are [tex]$45$[/tex] tables that are either round or located by the window.

Next, the probability that a customer will be seated at a table which is either round or by the window is the ratio of these favorable tables to the total number of tables:

[tex]$$
\text{Probability} = \frac{45}{60} = \frac{3}{4}.
$$[/tex]

Since the options are given in the form of [tex]$\frac{45}{60}$[/tex], the correct answer is

[tex]$$
\boxed{\frac{45}{60}}.
$$[/tex]