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------------------------------------------------ Riley cools a piece of silver with a mass of 5 kg from 45°C to 27°C. What is the change in thermal energy? (Cp = 235 J/kg-°C)

Answer :

Final answer:

The change in thermal energy of the silver piece as it cools from 45°C to 27°C is 21150 Joules by using the formula for thermal energy change.

Explanation:

To answer this question, we'll be using the formula for calculating a change in thermal energy, which is:

Q = m * Cp * ΔT

where:


  • Q is the thermal energy change,

  • m is the mass,

  • Cp is the specific heat capacity, and

  • ΔT is the change in temperature.


Given in the problem:



  • mass (m) = 5 kg,

  • specific heat capacity (Cp) = 235 J/(kg°C),

  • initial temperature = 45°C,

  • final temperature = 27°C.


Your ΔT would be initial temperature - final temperature, so ΔT = 45°C - 27°C = 18°C.


So we plug in these values to the formula:


Q = 5kg * 235 J/(kg-°C) * 18°C = 21150 J.


Therefore, the change in thermal energy of the silver piece as it cools from 45°C to 27°C is 21150 Joules.

Learn more about Change in thermal energy here:

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