Answer :
Final answer:
The change in thermal energy of the silver piece as it cools from 45°C to 27°C is 21150 Joules by using the formula for thermal energy change.
Explanation:
To answer this question, we'll be using the formula for calculating a change in thermal energy, which is:
Q = m * Cp * ΔT
where:
- Q is the thermal energy change,
- m is the mass,
- Cp is the specific heat capacity, and
- ΔT is the change in temperature.
Given in the problem:
- mass (m) = 5 kg,
- specific heat capacity (Cp) = 235 J/(kg°C),
- initial temperature = 45°C,
- final temperature = 27°C.
Your ΔT would be initial temperature - final temperature, so ΔT = 45°C - 27°C = 18°C.
So we plug in these values to the formula:
Q = 5kg * 235 J/(kg-°C) * 18°C = 21150 J.
Therefore, the change in thermal energy of the silver piece as it cools from 45°C to 27°C is 21150 Joules.
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