Answer :
a) Yes, the conditions for inference are satisfied because a random sample of 36 children was taken, the sample is less than 10% of the population, and the shape of the distribution is roughly bell-shaped.
b)Here, we need to perform the hypothesis test using p-value approach with significance level of 0.10.Hypothesis statements:
Null hypothesis:
H0 :
μ ≥ 32
Alternative hypothesis:
H1 :
μ < 32
Here,
μ denotes the population mean age at which gifted children first count to 10 successfully.
So, the test statistic can be calculated as shown below:
tscore=−1.304
where,
sample mean X = 29.8, population standard deviation σ = 5.2, sample size n = 36 and population mean μ0 = 32.
Since the alternative hypothesis is left-tailed, we should use a one-tailed test.
In order to find the p-value for the test statistic, we can use the t-distribution table for degrees of freedom (df) = n-1 = 35 and a significance level of 0.10.Using the table, we get:
p-value = P(T ≤ tscore)= P(T ≤ -1.304)= 0.1016
So, the p-value for the hypothesis test is 0.1016.
c)The p-value is greater than the significance level of 0.10.
Therefore, we do not have enough evidence to reject the null hypothesis.
We can conclude that the data does not provide convincing evidence that the average age at which gifted children first count to 10 successfully is less than the general average of 32 months.
Learn more about random sample from the given link
https://brainly.com/question/13219833
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