Answer :
Note that the force (F) required to hold the block in place on the inclined plane, assuming friction can be ignored, is approximately 2.8185 Newtons.
How to compute the above
To determine the force (F) required to hold the block in place on the inclined plane with an angle of elevation of 35 degrees, you need to consider the component of the gravitational force acting parallel to the slope.
The force of gravity (weight) acting on the block can be calculated as:
Weight (W) = mass (m) * gravitational acceleration (g)
Where:
- Mass (m) = 0.5 kg
- Gravitational acceleration (g) ≈ 9.81 m/s² (standard value on Earth)
W = 0.5 kg * 9.81 m/s² = 4.905 N
Now, you need to find the component of this weight force that acts parallel to the slope. This component is given by:
F_parallel = W * sin(θ)
Where:
- θ is the angle of elevation (35 degrees)
F_parallel = 4.905 N * sin(35°)
Now, calculate F_parallel:
F_parallel ≈ 4.905 N * 0.5736
F_parallel ≈ 2.8185 N
So, the force (F) required to hold the block in place on the inclined plane, assuming friction can be ignored, is approximately 2.8185 Newtons.
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