Answer :
Final answer:
Using a garden hose that delivers water at a rate of 9 gallons per minute to fill an Olympic-sized swimming pool would require approximately 51 days.
Explanation:
The question is asking how long it would take to fill an Olympic-sized swimming pool with a standard garden hose. First, we must understand the volume of the pool and the rate at which the hose can fill it. The volume of the pool is 6.6043 x 10^5 gallons, and the hose delivers water at a rate of 9 gallons per minute.
To find out how many minutes it would take to fill the pool, we simply divide the total volume by the rate of the hose: (6.6043 x 10^5 gallons) / (9 gallons/minute) = 73492 minutes. However, we are asked for the answer in days. There are 1440 minutes in a day, so to convert minutes into days, we use the formula: time (in days) = time (in minutes) / 1440.
Therefore, it would take 73492 minutes / 1440 = 51 days to fill the swimming pool if the hose was filling the pool 24 hours per day. This suggests that none of the answer choices provided are correct. Please check the problem again or consult your teacher for clarification.
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