Answer :
To solve the division problem [tex]\(7 \div 221\)[/tex], we want to divide 221 by 7 and find out both the quotient and the remainder. Let's go through the steps together:
1. Set Up the Division: We begin by setting up 221 inside the division bracket, and 7 outside.
2. Divide: Start by considering the first digit or group of digits in 221 that is larger than or equal to 7. In this case, we start with '22' since 7 cannot go into '2'.
3. First Division: Determine how many times 7 goes into 22. It goes in 3 times because [tex]\(3 \times 7 = 21\)[/tex] and 21 is the largest multiple of 7 that is less than or equal to 22.
4. Subtract and Bring Down: Subtract 21 from 22, which gives us a remainder of 1. Next, bring down the next digit in 221, which is '1', making it '11'.
5. Second Division: Now, determine how many times 7 goes into 11. It goes in 1 time because [tex]\(1 \times 7 = 7\)[/tex] and 7 is the largest multiple of 7 that is less than or equal to 11.
6. Final Subtraction: Subtract 7 from 11, which yields a remainder of 4.
7. Conclusion: Since there are no more digits to bring down, we have completed the division. Our quotient is 31 (from the tens place '3' and the ones place '1') and the remainder is 4.
Thus, when 221 is divided by 7, the quotient is 31 and the remainder is 4. So, the solution can be expressed as:
[tex]\[ 221 \div 7 = 31 \text{ remainder } 4 \][/tex]
1. Set Up the Division: We begin by setting up 221 inside the division bracket, and 7 outside.
2. Divide: Start by considering the first digit or group of digits in 221 that is larger than or equal to 7. In this case, we start with '22' since 7 cannot go into '2'.
3. First Division: Determine how many times 7 goes into 22. It goes in 3 times because [tex]\(3 \times 7 = 21\)[/tex] and 21 is the largest multiple of 7 that is less than or equal to 22.
4. Subtract and Bring Down: Subtract 21 from 22, which gives us a remainder of 1. Next, bring down the next digit in 221, which is '1', making it '11'.
5. Second Division: Now, determine how many times 7 goes into 11. It goes in 1 time because [tex]\(1 \times 7 = 7\)[/tex] and 7 is the largest multiple of 7 that is less than or equal to 11.
6. Final Subtraction: Subtract 7 from 11, which yields a remainder of 4.
7. Conclusion: Since there are no more digits to bring down, we have completed the division. Our quotient is 31 (from the tens place '3' and the ones place '1') and the remainder is 4.
Thus, when 221 is divided by 7, the quotient is 31 and the remainder is 4. So, the solution can be expressed as:
[tex]\[ 221 \div 7 = 31 \text{ remainder } 4 \][/tex]
