Object A, moving to the right at a speed of 4.00 m/s, collides head-on and completely inelastically with an identical object B moving to the left at a speed of 8.00 m/s. What occurs after the collision?

A. Object A moves to the left at 4.00 m/s, and object B moves to the right at 8.00 m/s.
B. Object A moves to the left at 8.00 m/s, and object B moves to the right at 4.00 m/s.
C. The objects move together to the right at a speed of 2.00 m/s.
D. The objects move together to the left at a speed of 2.00 m/s.
E. The objects both come to a stop (v = 0).

Answer: The answer is (d).
In a completely inelastic collision, the two objects stick together after the collision. Therefore, the objects will move together after the collision, and their final velocity will be somewhere between their initial velocities.

In this case, the initial velocities of the two objects are 4.00 m/s and 8.00 m/s. The final velocity of the two objects will be somewhere between these two values. The most likely outcome is that the two objects will move together to the left at a speed of 2.00 m/s. This is because the two objects have equal masses, so the final velocity will be closer to the velocity of the object with the lower initial velocity.

The other possible outcomes are that the two objects will move together to the right at a speed of 2.00 m/s, or that they will both come to a stop. However, these outcomes are less likely, as they would require the two objects to transfer more momentum to each other than is possible in a completely inelastic collision.

Learn more about inelastic here:
brainly.com/question/30103518

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