Five children in a family are weighed, and their weights are recorded as follows:

- Eli and Dave weigh 76 kg.
- Dave and Ann weigh 84 kg.
- Ann and Mark weigh 74 kg.
- Mark and Carol weigh 50 kg.
- Eli, Ann, and Carol weigh 100 kg.

Find the weight of each person.

Answer :

Final answer:

By solving the given equations algebraically, we find that Eli weighs 8kg, Ann 56kg, Mark 18kg, Carol 36kg, and Dave 28kg.

Explanation:

This problem is a matter of algebraic substitution.

Given the weights of Eli and Dave are 76kg, Dave and Ann 84kg, Ann and Mark 74kg, Mark and Carol 50kg, and Eli, Ann, and Carol together weigh 100kg.

You can form equations from this information and solve for each person's weight. First, from Eli and Dave's combined weight and Dave and Ann's combined weight, we know that Eli weighs 8kg less than Ann (76kg - 84kg = -8kg).

We then substitute Eli's weight into the equation for Eli, Ann, and Carol and find that Ann and Carol weigh the 100kg - 8kg = 92kg together.

Now, knowing Ann's weight is 92kg and Ann and Mark's weight together is 74kg, we can subtract to find Mark's weight:

92kg - 74kg = 18kg.

To find Ann's weight, subtract Mark's weight from Ann and Mark’s combined weight: 74kg - 18kg = 56kg.

We can find Carol's weight by subtracting Ann's weight from Ann and Carol's combined weight: 92kg - 56kg = 36kg.

Finally, we know Dave's weight to be 8kg more than Eli's, which gives 28kg for Dave.

  • Eli weighs 8kg
  • Ann 56kg
  • Mark 18kg
  • Carol 36kg
  • Dave 28kg.

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