Ms. Leong owned an ice cream store and had chocolate ice cream and vanilla ice cream for sale. She sold $\frac{3}{4}$ of the chocolate ice cream and $\frac{1}{2}$ of the vanilla ice cream. If, at the end of the day, she had 20 scoops of chocolate ice cream and 30 scoops of vanilla ice cream left, what is the total number of scoops of ice cream Ms. Leong had at the start of the day?

So, if Ms. Leong had x scoops of vanilla ice cream before she sold any, and she sold 1/2 of the ice cream and had 30 scoops left, she had an original 60 scoops of vanilla ice cream. Same with chocalate, y scoops, sold 3/4, and has 20 scoops of chocalate left, then she had original 80 scoops. 60+80=140
So, 140 scoops of icecream total.

Qwtea Qwtea · Answer 2 · 2025-03-10T10:53:07-04:00

Final answer:

Ms. Leong initially had 140 scoops of ice cream (80 chocolate and 60 vanilla) in her store.

Explanation:

The problem involves determining the initial amount of ice cream Ms. Leong had in her store. To solve it, we apply basic knowledge about fractions and work backwards. If, at the end of the day, Ms. Leong had 20 scoops of chocolate ice cream, and she had sold ¾ of chocolate ice cream, this means that 20 scoops represent ¼ (since 1 - ¾ = ¼) of the total chocolate ice cream. So, to get the total number of chocolate ice cream, we multiply 20 by 4, which gives us 80 scoops.

Similarly, for vanilla ice cream, she sold ½ at the end of the day and was left with 30 scoops. These 30 scoops represent ½ of the total number of vanilla ice cream scoops. We multiply 30 by 2 to get 60 scoops as the total number of vanilla scoops.

Therefore, the total number of ice cream scoops Ms. Leong had at the start of the day is 80 (chocolate) + 60 (vanilla) = 140 scoops.

Learn more about Fractions here:

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