College

Michael graphs the equations [tex]y=-\frac{1}{2} x+4[/tex] and [tex]y=x+1[/tex] to solve the equation [tex]-\frac{1}{2} x+4=x+1[/tex].

What are the solution(s) of [tex]-\frac{1}{2} x+4=x+1[/tex]?

Answer :

To solve the equation [tex]\(-\frac{1}{2} x + 4 = x + 1\)[/tex], let's go through the solution step-by-step. The goal is to find the value of [tex]\(x\)[/tex] that satisfies the equation.

1. Start with the original equation:

[tex]\[
-\frac{1}{2} x + 4 = x + 1
\][/tex]

2. Eliminate the fraction by multiplying every term by 2:

[tex]\[
2 \left(-\frac{1}{2} x + 4\right) = 2(x + 1)
\][/tex]

This simplifies to:

[tex]\[
-x + 8 = 2x + 2
\][/tex]

3. Get all terms involving [tex]\(x\)[/tex] on one side of the equation and constant terms on the other side:

Add [tex]\(x\)[/tex] to both sides:

[tex]\[
-x + 8 + x = 2x + 2 + x
\][/tex]

Which simplifies to:

[tex]\[
8 = 3x + 2
\][/tex]

4. Isolate the [tex]\(x\)[/tex]-term:

Subtract 2 from both sides:

[tex]\[
8 - 2 = 3x
\][/tex]

Which gives:

[tex]\[
6 = 3x
\][/tex]

5. Solve for [tex]\(x\)[/tex]:

Divide both sides by 3:

[tex]\[
x = \frac{6}{3}
\][/tex]

Therefore:

[tex]\[
x = 2
\][/tex]

The solution to the equation [tex]\(-\frac{1}{2} x + 4 = x + 1\)[/tex] is [tex]\(x = 2\)[/tex].